# 1143. Longest Common Subsequence
Question link is here.
Given an integer array nums
and an integer k
, return true
if it is possible to divide this array into k
non-empty subsets whose sums are all equal.
Given two strings text1
and text2
, return the length of their longest common subsequence. If there is no common subsequence, return 0
.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
- For example,
"ace"
is a subsequence of"abcde"
.
A common subsequence of two strings is a subsequence that is common to both strings.
Example 1:
Input: text1 = "abcde", text2 = "ace"
Output: 3
Explanation: The longest common subsequence is "ace" and its length is 3.
Example 2:
Input: text1 = "abc", text2 = "abc"
Output: 3
Explanation: The longest common subsequence is "abc" and its length is 3.
Example 3:
Input: text1 = "abc", text2 = "def"
Output: 0
Explanation: There is no such common subsequence, so the result is 0.
# Solution
Too busy to write solution idea, just post solution.
class Solution {
public int longestCommonSubsequence(String text1, String text2) {
int n = text1.length(), m = text2.length();
int[][] f = new int[n + 1][m + 1];
for (int i = 1; i <= n; ++i) {
for (int j = 1; j <= m; ++j) {
if (text1.charAt(i - 1) == text2.charAt(j - 1)) {
f[i][j] = f[i - 1][j - 1] + 1;
} else {
f[i][j] = Math.max(f[i - 1][j], f[i][j - 1]);
}
}
}
return f[n][m];
}
}